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If \(x\) cos 60° + y cos 0° = 3 and 4\(x\) sin 30° – y cot 45° = 2, then what is the value of \(x\)?(a) –1 (b) 0 (c) 1 (d) 2 |
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Answer» (d) 2 \(x\) cos 60° + y cos θ° = 3 ⇒ \(x\) x \(\frac12\) + y x 1 = 3 ⇒ \(x\) + 2y = 6 ...(i) and 4\(x\) sin 30° – y cot 45° = 2 ⇒ 4\(x\) x \(\frac12\) - y x 1 = 2 ⇒ 2\(x\) – y = 2 ...(ii) Now solve for x and y |
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