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If `x= cot A + cos A and y= cot A - cos A,` prove that `((x-y)/(x+y))^(2)+((x-y)/(2))^(2)=1.` |
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Answer» Adding , we get cosec `A=((x+y))/(2)implies sin A=(2) /((x+y)).` Subtracting , we get , cos `A=(x-y)/(2)` `therefore sin ^(2)+cos^(2)A=1implies ((2)/(x+y))^(2)+((x-y)/(2))^(2)-1=0.` |
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