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If X follows Binomial distribution with parameters n=5, p and P(X=2)=9P(X=3), then p is equal to ……. . |
Answer» `becauseP(X=2)=9cdotP(X=3)` (where, n=5 and q=1-p) `rArr""^(5)C_(2)p^(2)(1-p)^(3)=9cdot""^(5)C_(3)p^(3)(1-p)^(2)` `rArr(5!)/(2!3!)p^(2)(1-p)^(3)=9cdot(5!)/(3!2!)p^(3)(1-p)^(2)` `rArr(p^(2)(1-p)^(3))/(p^(3)(1-p)^(2))=9` `rArr((1-p)/p)=9rArr9p+p=1` `thereforep=1/10` |
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