InterviewSolution
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InterviewSolution
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If x = \((\frac{4}{5})^{-2}\div (\frac{1}{4})^{2}\), find the value of \(x^{-1}\) |
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Answer» x = \((\frac{4}{5})^{-2}\div (\frac{1}{4})^{2}\) On using, [Using \(a^{-n}=\frac{1}{a^{n}}\)] we get, x = \((\frac{5}{4})^{2}\div (\frac{1}{4})^{2}\) [Using and \(\frac{1}{a}\div \frac{1}{b}\)=\(\frac{1}{a}\times \frac{b}{1}\)] x = \((\frac{5}{4})^{2}\times (\frac{4}{1})^{2}\) x = \(\frac{5}{4}\times \frac{5}{4}\times 4\times 4\) x = 25 \(x^{-1} = \frac{1}{25}\) |
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