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If x is the average (arithmetic mean) of m and 9, y is the average of 2m and 15, and z is the average of 3m and 18, what is the average of x, y, and z in terms of m? |
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Answer» 2 m+9
y= 2 2m+15
Z= 2 3m+18
AVERAGE of x,y,z= 3 2 m+9
+ 2 2m+15
+ 2 3m+18
= 3 2 6m+42
=m+7 |
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