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If x J of work is done on a steady system, what is the heat for the system?(a) + x J(b) –x J(c) 0 J(d) None of the mentionedThis question was addressed to me in an interview.Question is taken from Energy balance for Different type of systems in chapter Miscellaneous of Chemical Process Calculation

Answer»

The CORRECT option is (b) –x J

To ELABORATE: CHANGE in the internal ENERGY for a steady-state system is always zero so Q + W= 0.



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