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If `x lt 6` and 17.5 is the mode of the following frequency distribution. `{:("Class-interval:", 0-5,5-10,10-15,15-20,20-25),("Frequency:", 5,2,3,6,x):}` Then, x =A. 3B. 2C. 4D. 5 |
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Answer» Correct Answer - A Clearly, 15-20 is the modal class such that `l=15, h=5, f=6, f_(1)=3 and f_(2)= x.` `therefore " mode"= l+(f-f_(1))/(2f-f_(1)-f_(2)) xx h` `rArr 17.5=15+(6-3)/(12-3-x)xx5 rArr 2.5x =7.5 rArrx=3` |
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