1.

The mean of the series `x_1, x_2,...x_n` is `barX`. If `x_2` is replaced by `lambda` then the new mean isA. `bar(X) + x_(2) + lambda`B. `(bar(X)-x_(2)-lambda)/(n)`C. `((n-1)bar(X)+lambda)/(n)`D. `(n bar(X)-x_(2)+lambda)/(n)`

Answer» Correct Answer - D


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