InterviewSolution
Saved Bookmarks
| 1. |
The mean of the series `x_1, x_2,...x_n` is `barX`. If `x_2` is replaced by `lambda` then the new mean isA. `bar(X) + x_(2) + lambda`B. `(bar(X)-x_(2)-lambda)/(n)`C. `((n-1)bar(X)+lambda)/(n)`D. `(n bar(X)-x_(2)+lambda)/(n)` |
| Answer» Correct Answer - D | |