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    				| 1. | If `x prop y^(2)` and y =4 when x =8 , if x =32 , then the positive value of y isA. 4B. 8C. 16D. 32 | 
| Answer» `x prop y^(2), therefore x=k.y^(2)` (where k=non -zero constant )…….(i) As per question , y =4 when x =8 `therefore` from (1) we get , 8 =k.`4^(2) ` or , 8 =16k or k=`(8)/(16)=1/2` `therefore` x =`1/2y^(2)` [from (1)]…….(2) Now ,putting x =32 in (2) we get , 32 =`1/2y^(2)` or , `Y^(2)`=64 or , y=`sqrt(64)=pm8`. `therefore` y =8 (taking positive value ) `therefore` (b) is correct. | |