1.

If `[x]` stands for the greatest integer function, then `[1/2+1/1000]+[1/2+2/1000]+...+[1/2+999/1000]`=

Answer» `[0.5+1/1000]+[0.5+2/1000]+...+[0.5+999/1000]`
There are total of 999 terms
`[0.5+1/1000]+[0.5+2/1000]+...+[0.5+4999/1000]`
There are total of 500 terms.
Option 3 is correct.


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