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If `[x]` stands for the greatest integer function, then `[1/2+1/1000]+[1/2+2/1000]+...+[1/2+999/1000]`= |
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Answer» `[0.5+1/1000]+[0.5+2/1000]+...+[0.5+999/1000]` There are total of 999 terms `[0.5+1/1000]+[0.5+2/1000]+...+[0.5+4999/1000]` There are total of 500 terms. Option 3 is correct. |
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