1.

If x=sum_(n=0)^(oo) cos^(2n) theta, y=sum_(n=theta)^(oo) sin^(2n) theta and z=sum_(n=0)^(oo) theta sin^(2n) theta, 0 lt theta lt pi/2. Then show that xyz=x+y+z.

Answer»


ANSWER :`(1)/((SIN^(2) THETA cos^(2) theta) (1-sin^(2) theta cos^(2) theta))`


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