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If \(x^{x\sqrt{x}} = (x\sqrt{x})^x. then\, x\,is\,equal\,to\)(a) \(\frac32\) (b) \(\frac29\) (c) \(\frac94\) (d) \(\frac49\) |
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Answer» (c) \(\frac94\) ⇒ \(x^{x\sqrt{x}} = (x^{\frac32})^x\) ⇒ \(x^{x\sqrt{x}} =x^{\frac{3}{2}x}\) ⇒ \(x\sqrt{x} = \frac32x ⇒\sqrt{x} =\frac32⇒x=\frac94.\) |
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