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If (x+y) = 10 and xy = 10, find the value of (x2 + y2). |
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Answer» Property USED = (x+y)² = x² + 2XY + y²Now PUTTING the value(10)² = x² + 2 (10) + y²100 = x² + 20 + y²100 - 20 = x² + y²80 = x² + y²Plzz mark me as brainliest |
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