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. If x + y = 12 and xy = 32, Find the value of x2 + y2 |
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Answer» Answer: Given that: x+y=12 and XY = 32 Using the given IDENTITY (x+y) = x 2 +2xy+y 2
⇒ (12) 2 =x 2 +64+y 2
⇒ 144 = x 2 +y 2 +64 ⇒ 144−64 = x 2 +y 2
⇒ 80 = x 2 +y 2
The answer is x 2 +y 2 = 80 please mark me a BRAINLIEST |
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