1.

If x+y =12 and xy=32 then find the value of xpower2 + ypower2

Answer»

Answer:

given, x+y = 12 and XY = 32

(6 this is POWER)

Step-by-step explanation:

(x+y)^2 = x^2 + y^2 + 2XY

(12)^2 = x^2 + y^2 + 2 X 32

(144) = x^2 + y^2 + 64

144-64 = x^2 + y^2

80 = x^2 + y^2

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