If (x-y)² = 121xy , then 2log (x+y) =

1.	If (x-y)² = 121xy , then 2log (x+y) =
Answer» *Question:— if (X-y)² = 121xy , then 2LOG (x+y) = ? *Answer:— From [1] :— → (x - y)² = 121xy → x² + y² - 2xy = 121xy → x² + y² + 2xy = 125xy → (x + y)² = 125xy Applying LOG on both the sides :— → log(x + y)² = log(125xy) → 2log(x + y) = log125 + log(x) + log(y) ____[3] From [2] and [3] :— → k = log25 Hope it helps you. $@vikramjeeth$

Answer»

*Question:—

if (X-y)² = 121xy , then 2LOG (x+y) = ?

*Answer:—

From [1] :—

→ (x - y)² = 121xy

→ x² + y² - 2xy = 121xy

→ x² + y² + 2xy = 125xy

→ (x + y)² = 125xy

Applying LOG on both the sides :—

→ log(x + y)² = log(125xy)

→ 2log(x + y) = log125 + log(x) + log(y) ____[3]

From [2] and [3] :—

→ k = log25

Hope it helps you.

$@vikramjeeth$

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If (x-y)² = 121xy , then 2log (x+y) = ​