InterviewSolution
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InterviewSolution
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If `x , y in [0,2pi]`, then find the total number of ordered pairs `(x , y)`satisfying the equation `sinxcosy=1` |
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Answer» `sin x cos y=1` `rArr sin x=1, cos y=1 or sin x=-1, cos y =-1` If `sin x=1. cos y=1`, hence, `x=pi//2, y=0, 2pi` If `sin x=-1, cos y =-1`, hence, `x=3pi//2, y=pi` Thus, the possible ordered ordered pairs are `(pi/2, 0), (pi/2, 2pi)` and `((3pi)/2, pi)`. |
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