If `x+y=k`is normal to `y^2=12 x ,`then `k`is3 (b) 9(c) `-9`(d) `-3`A. 3B. 9C. -9D. -3

If `x+y=k`is normal to `y^2=12 x ,`then `k`is3 (b) 9(c) `-9`(d) `-3`A.

1.	If `x+y=k`is normal to `y^2=12 x ,`then `k`is3 (b) 9(c) `-9`(d) `-3`A. 3B. 9C. -9D. -3
Answer» Correct Answer - B Let `x+y=k` be normal to `y^(2)=12xx at p(alpha,beta)" "...(i)` `thereforebeta^(2)=12 alpha" "...(ii)` Also, slope of normal at `P(alpha, beta)` is -1 From, Eq. (i), `(dy)/(dx)=6/y` `implies((dy)/(dx))_(p)=(6)/(beta)` `therefore -1 =(-1)/(6//beta)` `impliesbeta=6,alpha =3` `thereforeP` is (3,6) which lies on `x+y=k` `therefore 3+6=k` `impliesk=9`

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If `x+y=k`is normal to `y^2=12 x ,`then `k`is3 (b) 9(c) `-9`(d) `-3`A. 3B. 9C. -9D. -3

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