If x,y,z=0 then show that x3+y3+z3=3xyz

1.	If x,y,z=0 then show that x3+y3+z3=3xyz
Answer» Answer: Step-by-step explanation: GIVEN, X3 + y3 + Z3 = 3xyz Therefore, x3 + y3 + z3 - 3xyz =0 This means, x3 + y3 + z3 - 3xyz = (x + y + z) (x2 + y2 + z2 - xy - yz - ZX) Now if x + y + z = 0, then...... x3 + y3 + z3 - 3xyz = ( 0 ) (x2 + y2 + z2 - xy - yz - zx) . . . . . . .... ..... ... .. . . .. . ..... [ subsituting the value of x + y + z ] x3 + y3 + z3 - 3xyz = 0 x3 + y3 + z3 = 3xyz . If this answer helps you..plz don’t forget to mark me as the BRAINLIEST answer..!

Answer»

Answer:

Step-by-step explanation:

GIVEN, X3 + y3 + Z3 = 3xyz

Therefore, x3 + y3 + z3 - 3xyz =0

This means,

x3 + y3 + z3 - 3xyz = (x + y + z) (x2 + y2 + z2 - xy - yz - ZX)

Now if x + y + z = 0, then......

x3 + y3 + z3 - 3xyz = ( 0 ) (x2 + y2 + z2 - xy - yz - zx) . . . . . . .... ..... ... .. . . .. . ..... [ subsituting the value of x + y + z ]

x3 + y3 + z3 - 3xyz = 0

x3 + y3 + z3 = 3xyz .

If this answer helps you..plz don’t forget to mark me as the BRAINLIEST answer..!

Discussion