1.

If `x:y:z=3:3:5 and x^(3)+y^(3)+z^(3)=1728`, then find `(x-y+z)`

Answer» let x=3a, y=4a and z=5a
Given `x^(3)+y^(3)+z^(3)=1728`
`(3a)^(3)+(4a)^(3)+(5a)^(3)=1728`
`216a^(3)=1728`
`a^(3)=8`
`a=2`
`x-y+z=3a-4a+5a`
`=4a=4(2)=8`.


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