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    				| 1. | If x, y, z are in A.P. and A1is the A.M. of x and y, and A2 is the A.M. of y and z, then prove that the A.M. of A1 and A2 is y. | 
| Answer» Given that, A1 = AM of x and y And A2 = AM of y and z So, A1 = (x + y)/2 A2 = (y + x)/2 AM of A1 and A2 = (A1 + A2)/2 = [(x + y)/2 + (y + z)/2]/2 = [x + y + y + z]/2 = [x + 2y + z]/2 Since x, y, z are in AP, y = (x + z)/2 AM = [(x + z/2) + (2y/2)]/2 = (y + y)/2 = 2y/2 = y Hence proved. | |