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If `x,y,z` be three numbers in `G.P.` such that `4` is the `A.M.` between `x` and `y` and `9` is the `H.M.` between `y` and `z` , then `y` isA. `4`B. `6`C. `8`D. `12` |
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Answer» Correct Answer - B `(b)` Let `x=(k)/(r )`, `y=k`, `z=kr` `implies((k)/(r )+k)/(2)=4` ……..`(i)` and `(2k*kr)/(k+kr)=9` ………`(ii)` Solving we get `k=6` |
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