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If x3 + ax2 + bx + 6 has (x – 2) as a factor and leaves a remainder 3 when divided by (x – 3) |
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Answer» a=-3,b=-1 Step-by-step explanation X^3+ax^2+bx+6 x-2 is factor x-2=0 x=2 2^3+a2^2+2b+6=0 8+4a+2b+6=0 4a+2b=-14 2a+b=-7-eqn-1 x^3+ax^2+bx+6 is DIVED by x-3 so x-3=0 x=3 3^3+9a+3b+6=3 9a+3b=-30 3a+b=-10-eqn-2 from eqn-1&2 a=-3&b=-1
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