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If `y=2x+3`is a tangent to the parabola `y^2=24 x ,`then find its distance from the parallel normal. |
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Answer» Correct Answer - `(75)/(sqrt(5))` The equation of normal to the parabola `y^(2)=24x` having slope m is `y=mx-12m-6m^(3)`. It is parallel to y=2x+3. Therefore, m=2. Then the equation of the parallel normal is y=2x-24-48=2x-72 The distance between y=2x+3 and y=2x-72 is `|(72+3)/(sqrt(4+1))|=(75)/(sqrt(5))` |
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