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If `y=Asin mx+B cos mx`, then prove that`(d^2y)/(dx^2)+m^2y=0` |
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Answer» `y = Asinmx+Bcosmx` `dy/dx = Amcosmx-Bmsinmx` `(d^2y)/dx^2 = -Am^2sinmx-Bm^2cosmx` `(d^2y)/dx^2 = -m^2(Asinmx+Bcosmx)` `(d^2y)/dx^2 = -m^2(y)` `(d^2y)/dx^2 + m^2(y) = 0` |
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