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If `y=sin^(-1)(3x)+sec^(-1)((1)/(3x)),` find `(dy)/(dx)`. |
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Answer» `t=sin^(-1)(3x)+sec^(-1)((1)/(3x))` `y=sin^(-1)(3x)+cos^(-1)(3x)(because sin^(-1).(1)/(x)=cos^(-1)x)` `y=(pi)/(2)" "(because sin^(-1)x+cos^(-1)x=pi//2)` Differentiating w.r.t. x, we get `(dy)/(dx)=0` |
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