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If y = sin(lnx), then which one of the following is correct?a. d2y/dx2 + y = 0b. d2y/dx2 = 0c. x2(d2y/dx2) + x(dy/dx) + y = 0d. x2(d2y/dx2) - x(dy/dx) + y = 0 |
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Answer» Correct option c. x2(d2y/dx2) + x(dy/dx) + y = 0 Explanation: y = sin(logx) ⇒ dy/dx = (cos(logx))/x ⇒ x(dy/dx) = cos(logx) Again, Differentiating, x(d2y/dx2) + dy/dx = (sinlogx/x) = -y/x ⇒ x2(d2y/dx2) + x(dy/dx) + y = 0 |
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