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                                    If y1(x) is a solution of the differential equation dydx−f(x)y=0, then a solution of the differential equation dydx+f(x)y=r(x) | 
                            
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Answer»  If y1(x) is a solution of the differential equation dydx−f(x)y=0, then a solution of the differential equation dydx+f(x)y=r(x)  | 
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