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If `z=4+isqrt(7)`, then find the value of `z^3-4z^2-9z+91.` |
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Answer» `z = 4 + I sqrt(7)` or ` x z- 4 = isqrt(7)` or ` z^(2) - 8z + 16 = - 7` or ` z^(2) - 8z + 23 = 0` Now dividing `z^(3) - 4z^(2) - 9z + 91 ` by `z^(2) - 8z + 23` we get `z^(3) - 4z^(2) - 9 z + 91 = (z^(2) - 8z + 23) (z +4) - = -1`. |
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