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Ifabs(vecA+vecB)=abs(vecA-vecB) find the angle between vecA and vecB. |
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Answer» SOLUTION :Let `theta` be the angle between `vecA` and `vecB` Given `ABS(vecA+vecB)=abs(vecA+vecB)=abs(vecA-vecB)` `THEREFORE abs(vecA+vecB)^2=abs(vecA-vecB)^2` `vecAcdotvecA+vecBcdotvecB+2vecAcdotvecB=vecAcdotvecA+vecBcdotvecB-2vecAcdotvecB or `4vecAcdotvecB`=0 since A&B are non zero `costheta=0 or `theta=90^@` |
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