1.

Ifacos2theta+bsin2theta=c" has "theta_(1),theta_(2)as its solutions then show that tantheta_(1)+tantheta_(2)=(2b)/(c+a)tantheta_(1).tantheta_(2)=(c-a)/(c+a) and hence show that tan(theta_(1)+theta_(2))=b//a.

Answer»


ANSWER :`(B)/(a)`


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