1.

IfK_(sp)of M(OH)_(3) is 1 xx 10^(-12) then 0.001 M.M^(2+) isprecipitate in a pH gt 9

Answer»


Solution :`M(OH)_(3) `is PRECIPITATE
`[M^(3+)][OH^(Theta)]^(3) gt K_(sp) [OH^(Theta)]^(3)gt 1 XX 10^(-9)`
`[OH^(Theta)] gt 1 xx 10^(-3)`
Maximum `pOH = 3` Minimum `pH = 9`
Hence true.


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