InterviewSolution
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ी 1८% olहल ~ व न.्् 10 कि : 4;*’ e |
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Answer» Theelectric flux(φ) through curved surface = ϐ E ds cos θ φ = ϐ E ds[we know, θ = 0; cosθ = 1] = E (2πrl) (The surface area of the curved part is 2πrl) Since E→and ds→are right angles to each other, the electric flux through the plane caps = 0 so, Total flux through the Gaussian surface,φ = E. (2πrl) The net charge enclosed by Gaussian surface is,q = λl By Gauss’s law,E (2πrl) = λl/ε0 or,E = λ / 2πε0r |
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