1.

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Answer»

Theelectric flux(φ) through curved surface = ϐ E ds cos θ

φ = ϐ E ds[we know, θ = 0; cosθ = 1]

= E (2πrl)

(The surface area of the curved part is 2πrl)

Since E→and ds→are right angles to each other, the electric flux through the plane caps = 0

so, Total flux through the Gaussian surface,φ = E. (2πrl)

The net charge enclosed by Gaussian surface is,q = λl

By Gauss’s law,E (2πrl) = λl/ε0

or,E = λ / 2πε0r



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