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II. The train crosses another train 100 m long coming from the opposite direction at 72 km/hr in 6.4 sec.1). Only I2). Only II3). Both I and II4). Either I or II |
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Answer» Let the length of the train be ‘y’ m Considering statement I, Speed of train = length of train/time taken to cross signal post = (y/8) m/sec. Considering statement II, ? Another train is coming from opposite direction, the relative speed is the sum of the individual speeds Speed of other train = 72 km/hr = 72 × 5/18 = 20 m/sec. Using information from statement I, Relative speed = 20 + y/8 Time taken to cross the train = sum of the lengths of train/relative speed ⇒ 6.4 = (y + 100)/(20 + y/8) ⇒ 128 + 0.8y = y + 100 ⇒ 0.2y = 28 ⇒ y = 28/0.2 = 140 m ∴ Both the STATEMENTS are necessary to ANSWER the question |
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