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(ii) x2 – 2kx + 7k - 12 = 0. |
Answer» X2-2kx+7k-12=0A = 1 , B = -2k , C = 7k-12d = b^2 - 4AC= 4k^2 - 4 × 1 × 7k-12= 4k^2 - 28K + 48=0= k^2 - 7k + 12 = 0= (k-4) (k-3) = 0= k = 4 , k = 3ᏴᎬ ᏴᎡᎪᏆNᏞY |
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