Impure coppercontaining Fe,Au ,Ag as impuritiesis elecrolyticallyrefined A currentof 140 A for 482.25 s decreasedthe massof theanodeby 22.26 g and increased the mass of cathode by 22.011 g percentageof iron in impure copper is (Given molar mass of Fe =55.5 mol^(-1) molar mass of Cu =63.54 g mol^(-1))

Impure coppercontaining Fe,Au ,Ag as impuritiesis elecrolyticallyrefin

1.	Impure coppercontaining Fe,Au ,Ag as impuritiesis elecrolyticallyrefined A currentof 140 A for 482.25 s decreasedthe massof theanodeby 22.26 g and increased the mass of cathode by 22.011 g percentageof iron in impure copper is (Given molar mass of Fe =55.5 mol^(-1) molar mass of Cu =63.54 g mol^(-1))
Answer» 0.95 0.85 0.97 0.9 Solution :AMOUNT pf impurity =decreased mass of anode - increased mass of cathode amountof pure Cu DEPOSITED `W=Zit =(C )/(96500)xxit` `=(63.54)/(2xx96500)xx140 xx482.5`=22.239 g `therefore`amountof impurity (Fe) = 22.239 -22.011 = 0.228 g Now from FARADAY SECOND law of electrolysis `("weightof fe deposited")/(0.228) =(27.55)/(31.77)` `therefore` Weight of Fe `=(27.75 xx0.288)/(22.26) xx100=0.88 =0.09`