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In 10^3 Litre sample of hard water CaSO_4 and MgSO_4 is present.If elevation in Boiling point is 0.000052^@C.Calculate the degree of Hardness of hard water .(K_b for H_2O=0.52)

Answer»


SOLUTION :`DeltaT_b=DeltaT_(b_1)=DeltaT_(b_2)`
`DeltaT_b=0.0000104=(m_1i_1+m_2i_2)xxk_b`
`{:(CaSO_4,MgSO_4),(i=i_1,i'=i_2),(n=n_1,n'=n_2):}`
`0.000052=((n_1+n_2)xx0.52xx2)/10^6xx1000`
`n_1+n_2=0.05`
for DEGREE of Hardness
`n_(CaSO_4)+n_(MgSO_4)=n_(CaCO_3) " " n_1+n_2=n_(CaCO_3)`
`n_(CaCO_3)=0.05`
`m_(CaCO_3)=0.05xx100=5` gm
degree of hardness=`5/10^6xx10^6=5` ppm


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