1.

In 100 g of naphthalene, 2.423 g of S was dissolved. Melting point of naphthalene =80.1^(@)C,DeltaT_(f)=0.661^(@)C,L_(f)=35.7"cal/g" of naphtahalene. Molecular formula of sulphur added is

Answer»

`S_(2)`
`S_(4)`
`S_(6)`
`S_(8)`

SOLUTION :`M_(2)=(1000K_(f)w_(2))/(w_(1)DeltaT_(f))=(1000w_(2))/(w_(1)DeltaT_(f))xx(RT_(0)^(2))/(1000L_(f))`
`=(1000xx2.423)/(100xx0.661)xx(2XX(353.1)^(2))/(1000xx35.7)="256 g mol"^(-1)`
If `S_(x)` is the formula, then MOLECULAR mass `x xx 32 = 56 or x = 8`.


Discussion

No Comment Found

Related InterviewSolutions