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                                    In 5 g atom of Ag(At wt of Ag = 108), calculatethe weight of one atom of Ag- | 
                            
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Answer»  Ag has atomic mass of 108 which is equal to its 1 mole. Acc to avagadro number 1 mole has 6.O23×10^23 atoms . Which means 108 g of Ag contains 6.023×10^23 atoms. Therefore 5 g of silver will have : O.28 × 10^23 atoms. ok thanks  | 
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