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In a AABC, the ratio of ZBAC and ZABC is 6:7 and 2C = 50. Find the value of BAC and ABC |
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Answer» Here, we can see that ∠BAC∠BAC is BISECTED by AD where AD TOUCHES BC at D. BC=BD+DCBC=BD+DCwhere, BC=3cmBC=3cm. We also have the VALUES of ADJACENT sides AB=6cmAB=6cmand AC=5cmAC=5cm.These satisfy the requirements of angle bisector theorem. Then, by the theorem, we have:ABBD=ACDCABBD=ACDC⇒DC=AC∗BDAB=5∗36=2.5cm⇒DC=AC∗BDAB=5∗36=2.5cmHappy math!! |
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