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In a arrangement of Young experiment the central fringe of interference pattern produced by light of wavelength 6000 Å so the central fringe is superposing to 4th order dark fringe, after a glass plate of refractive index 1.5 is introduced. The thickness of the glass plate would be ...... |
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Answer» `6xx10^(-6)m` but `(xd)/(D)=(2n-1)(lambda)/(2)` `(xd)/(D)=(7lambda)/(2) ""...(2) n=4` dark `:.` From equation (1) and (2), `t=(7lambda)/(2(mu-1))` `=(7xx6xx10^(-7))/(2(1.5-1.0))=(21xx10^(-7))/(0.5)=4.2xx10^(-6)m` |
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