1.

In A^(=)B^(-) ionic compound radii of A^(=) and B^(-) ions are 180 pmand 187 pm respectively .The crystal structure of this compound will be

Answer»

`NaCI` type
`CACI` type
`ZnS` type
SIMILAR to diamond

SOLUTION :`r_(+) // r_(-) = (180)/(187) = 0.962 `which lies in the range of `0.732 - 1.000` hence coordination number `= 8 `i.e. the STRUCTURE is `CaCI` type.


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