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In a bank principal increases at the rate of r%per year. Find the value of r if Rs. 100 double itself in 10 years `((log)_e2=0. 6931.)` |
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Answer» `(dP)/(dt)=(r )/(100)*Pimplies(dP)/(P)=(r )/(100)dt` `implies logP=(r )/(100)t+c` Let at `t=0`, `P=P_(0)` `:. logP_(0)=0+cimpliesc=logP_(0)` Now, `logP=(rt)/(100)+logP_(0)` `implies log(P)/(P_(0))=(rt)/(100)` Given at, `t=10`, P=2P_(0)` `:. log"(2P_(0))/(P_(0))=(r(10))/(100)=(r )/(10)=log2=0.6931` `implies r=6.931 %` |
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