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In a betatron the magnetic flux across an equilibrium orbit of radiusr = 20 cmvaries duringa timeintervalDelta t = 1.0 ms at practicallyconstantratefrom zeroto B = 0.40 T. Find the energy acquiredby theelectron per revolution. |
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Answer» SOLUTION :From the betatron condition, `(1)/(2) (d)/(dt) lt B gt = (dB)/(dt) (r_(0)) = (B)/(Delta t)` Thus, `(d)/(dt) lt B gt = (2B)/(Delta t)` and `(d PHI)/(dt)=PI r^(2) (d lt B gt)/(dt) = (2pi r^(2) B)/(Delta t)` So, energy increment per revolution is, `e (d Phi)/(dt) = (2pi r^(2) eB)/(Delta t)` |
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