1.

In a biprism experiment, a slit is illuminated by a light of wavelength `4800`. The distance between the slit and biprism is and the distance between the biprism is `15cm` and the distance between the biprism and eyepiece is `85cm`. If the distance between virtual sources is `3mm`, determine the distance between `4th` bright band on one side and `4th` dark band on the other side of the central bright band.

Answer» Given : ` lambda =4800=4800xx10^(-10)m`
`D=85+15=100cm=1m`
`d=3mm=3xx10^(-3)m`
Distance of `4th` bright band on one side
`=(4Dlambda)/(d)`
`=(4xx1xx4800xx10^(-10))/(3xx10^(-3))`
`=6.4xx10^(-4)m`
`4th` dark band on the other side
`=(m-(1)/(2))(Dlambda)/(d)`
`=((4-(1)/(2))xx4800xx10^(-10)xx1)/(3xx10^(-3))`
`=0.00056`
`=5.6xx10^(-4)m`
`:.` Total distance `=5.6xx10^(-4)+6.4xx10^(-4)`
`=1.2xx10^(-3)m`.


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