1.

In a biprism experiment,fringe width is 0.4 mm when the eypiece is at a distance of 1 mm from theslit. If eyepieceis moved without changing any other arrangment then the change in fringe width is

Answer»

`0.1 mm `
`0.2 mm`
`0.15 mm`
`0.25mm`

Solution :`beta_(2)=(D_(2))/(D_(2)) beta_(1)=(0.75xx0.4xx10^(-3))/(1) 0.3 mm`
THUS, change in FRING width is,
`beta_(1)-beta_(2)=0.4-0.3=0.1 mm`


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