In a biprism experiment, the eye piece was palced at a distance of 20 cm from the source.The distance between two virtual sources was found to be 0.075 cm. Find the wavelength of source of light if the eye piece ahs to be moved through a distance of 1.888 cm for 20 fringes to cross the field of view :

In a biprism experiment, the eye piece was palced at a distance of 20

1.	In a biprism experiment, the eye piece was palced at a distance of 20 cm from the source.The distance between two virtual sources was found to be 0.075 cm. Find the wavelength of source of light if the eye piece ahs to be moved through a distance of 1.888 cm for 20 fringes to cross the field of view :
Answer» `5900 Å` `2400 Å` `3200 Å` `4500 Å` Solution :D = 120 cm = 1.2m, d = `7.5 xx 10^(-4)`m `beta = (x)/(N) = (1.888)/(20)cm = 0.0944 cm` Now `beta = (Dlambda)/(d), lambda = 5.9 xx 10^(-7) m = 5900Å`

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