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In a biprism experiment, the fringe width is 1.4mm with light of wavelength 6000 Å. What will be the fringe width if light of wavelength 5400 Å is used, with no other change in the experimental setup? |
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Answer» SOLUTION :`X_(2)/X_(1) = lambda_(2)/lambda_(1)` `therefore` The new fringe width, `X_(2) = (lambda_(2))/(lambda_(1))X_(1) = (5400)/(6000) xx 1.4` `=0.9 xx 1.4 = 1.26` mm |
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