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| 1. |
In a biprism experimentn the distance between thetwo virtual images of the slite in the magnified and diminished position are 2.4 mm and 0.6 resepectively. The distance the two virtual images of the slit is |
| Answer» SOLUTION :`d=SQRT(d_(1)d_(1))= sqrt(2.4xx0.6)=1.2 mm` | |