1.

In a box, there are 8 red, 7 blue and 6 green balls. One ball is picked up randomly. What is the probability that it is neither blue nor green?

Answer»

8/21



Total number of BALLS = (8 + 7 + 6) = 21
Let E = event that the ball drawn is NEITHER blue nor green =e VENT that the ball drawn is red.
Therefore, n(E) = 8.
P(E) = 8/21.



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